I feel that my code is unnecessarily long. Therefore, I would like to know whether I could make this program shorter and more efficient. Python strings supports Python built-in len function. The key keyword argument is a pattern you'll see frequently in python. It accepts a function as an argument in our case len. This solution is not a great fit if you need to know when two strings are of equal length. If that's a requirement of yours, you'd be better off using a solution from one of the other answers.
I won't bother updating this approach to handle that requirement: that would feel like working against the language. It is customary for code that starts executing a series of commands to be surrounded in a special if -block:.
Python | Remove given character from Strings list
Particularly once you've put your code inside a main block, the multiple levels of indentation can get a little messy quickly. It helps to put some of the code into a method and then call it, rather than just have it all in sequence:.
You can reduce your if block to just two conditions by testing for equal lengths first and using a ternary:. This allows you to avoid repeating the print "Larger string is:" line without having to move that message to a variable. It could refer to lexical sorting, for example. We could differentiate between character and byte length, if that won't be clear from context, but character length is the usual assumption and is what you get from Python 3 by default.
Read PEP8 for Python's standards on the use of spaces around parentheses, indentation length, and blank lines.
Your team might define their own standards, but PEP8 is the industry default. You'll note I also shortened the variables down to s1 and s2. You usually want meaningful variable names, but there's no semantic meaning to these variables to capture in the name since it's just two arbitrary strings, so s1 doesn't really lose anything over string1. I also want to note that I considered separating out the print ing from actually picking which string to print.
I decided not to separate them because the case of equal lengths was handled differently.Given an array of lower case strings, the task is to find the number of strings that are distinct.
Two strings are distinct if on applying the following operations on one string the second string cannot be formed. A simple solution is to run two loops. The outer loop picks a string and inner loop checks if there is a previously string which can be converted to current string by doing allowed transformations.
This solution requires O n 2 m time where n is number of strings and m is maximum number of characters in any string. An efficient solution generate an encoded string for every input string. The encoded has counts of even and odd positioned characters separated by a separator.
Two strings are considered distinct if their encoded strings are same else not. Once we have a way to encode string, the problem reduces to counting distinct encoded strings.
This is a typical problem of hashing. We create hash set and one by one store encodings of strings. If an encoding already exists, we ignore string. Else we store encoding in hash and increment count of distinct strings. This article is contributed by kp If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.
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Python - Strings
Please use ide. A character on odd index can be swapped with another character at odd index only. A character on even index can be swapped with another character on even index only. So there are 2 distinct strings as the third string cannot be converted to the first. Python3 program to count distinct strings with. Returns encoding of string that can be used. The idea is to return same encoding. OR swapping an odd character with other odd characters.
For every character from 'a' to 'z', we store its. This function basically uses a hashing based set to. Create an empty set and store all distinct.
If this encoding appears first time, increment. This code is contributed by. Contains encodeString input[i]. Add encodeString input[i]. ToCharArray .Sometimes, while working with Python list, we can have a problem in which we need to remove a particular character from each string from list. This kind of application can come in many domains. In this, we iterate through each string and replace specified character with empty string to perform removal.
In this, we offer a one-liner solution to this problem compacting the code using similar method as above. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.
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Remove character from Strings list. Output : The original list : ['gfg', 'is', 'best', 'for', 'geeks'] The list after removal of character : ['gfg', 'i', 'bet', 'for', 'geek'].
Change your preferences any time. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. I'm sure there is a simple Python way of doing this but I can't work it out, any help and explanation appreciated. Its called Longest Common Substring problem. Here I present a simple, easy to understand but inefficient solution. For completeness, difflib in the standard-library provides loads of sequence-comparison utilities. Example use:.
One might also consider os. The same as Evo'sbut with arbitrary number of strings to compare:. In this case, we should have 'hist' and 'home' as a result. Furthermore, it differs if the order of arguments is changed. So I change the code to find every block of substring and it results a set of common substrings:.
This isn't the most efficient way to do it but it's what I could come up with and it works. If anyone can improve it, please do. What it does is it makes a matrix and puts 1 where the characters match. Then it scans the matrix to find the longest diagonal of 1s, keeping track of where it starts and ends.
Then it returns the substring of the input string with the start and end positions as arguments. Note: This only finds one longest common substring. If there's more than one, you could make an array to store the results in and return that Also, it's case sensitive so Apple pie, apple pie will return pple pie.
This is the classroom problem called 'Longest sequence finder'. I have given some simple code that worked for me, also my inputs are lists of a sequence which can also be a string:. First a helper function adapted from the itertools pairwise recipe to produce substrings.
Then a function the iterates over substrings, longest first, and tests for membership. Learn more. Find common substring between two strings Ask Question. Asked 6 years, 7 months ago. Active 1 month ago. Viewed 77k times. I'd like to compare 2 strings and keep the matched, splitting off where the comparison fails. NorthSide NorthSide 1 1 gold badge 7 7 silver badges 14 14 bronze badges.
Longest common substring problem. Also check out algorithm implementations on wikibooks: en. The content of the question does not correspond to what is in the title.Please Login in order to post a comment. This is really nice solution. Just one problem though assuming above code is in JAVA if you give input bacb. It still returns NO.
This will fix the problem. There won't be any problem iof we check against Becasue what you are telling is correct for a String comparison. Here it is character. It will still return YES because "b" is a subset of "bac". The multiple depends on how many letters are in each set. But yours should be O N not Omega Nif you break on the first match, and could easily be quicker than set intersection, which always generates the complete intersection set.
It would depend on the input; and who knows what the average case would be. You don't need to use maps. All you need are 3 strings. Your code only works with english abecedary, you may also have to consider italian, french, chinesse, japanese, korean, latin, greek It checks if the string was found since the string::find function return the pos of the letter which you searched for.
This excercise is all about dictionaries and hashtables, so I suggest using them, otherwise you could fail an interview test by not practicing them. But in your solution you compare each char from "letters" with each char in s1 and each char in s2. Congratulations, you avoided using set or map by making it perform in quadratic time instead of linear time. Each iteration takes N units of time because indexOf do sequential search each time you are trying to find some character and you are searching for it 26 times.
The overall time is about 26N. A better approach is to store 26 boolean flags for each character of each words and check if their boolean flags intersect, if any of the flag intersect then 2 words are common. This approach only scans through each words once. Since the characters are in the range a-z, doing ch-'a' makes the character withinmuch in the range of int 32bitsso now ORing the respective bit after shifting it to its place makes it 1.
It's not needed to call the 2nd letterBits for strBit's enough to check if at least 1 letter of strB exists in bitsA. How do you compare char to int?
With extra functionality? Why do you need it? There's no runtime complexity to win. But this excercise is all about dictionaries and hashtables, so I suggest using them, otherwise you could fail an interview test by not practicing them. I would not have thought of solving it that way right off the bat. Nice work!Sorry, You don't have enough Tech Quotient to apply for this job. Please participate in the Skill test for skills given below in order to earn Tech Quotient and then apply again.
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Update Password. Customize TechGig Save your time. Get all your tech needs at one place. Social Login. Subscribe To Our Newsletter. You will start getting newsletters from tomorrow. Re-Authenticate Login. Autocomplete Your Profile.String literals in python are surrounded by either single quotation marks, or double quotation marks. Assigning a string to a variable is done with the variable name followed by an equal sign and the string:.
Note: in the result, the line breaks are inserted at the same position as in the code. Like many other popular programming languages, strings in Python are arrays of bytes representing unicode characters.
However, Python does not have a character data type, a single character is simply a string with a length of 1. Specify the start index and the end index, separated by a colon, to return a part of the string.
Get the characters from position 5 to position 1, starting the count from the end of the string:. The strip method removes any whitespace from the beginning or the end:. The split method splits the string into substrings if it finds instances of the separator:. To check if a certain phrase or character is present in a string, we can use the keywords in or not in.
Merge variable a with variable b into variable c :. But we can combine strings and numbers by using the format method! The format method takes unlimited number of arguments, and are placed into the respective placeholders:. An example of an illegal character is a double quote inside a string that is surrounded by double quotes:.
You will get an error if you use double quotes inside a string that is surrounded by double quotes:. Note: All string methods returns new values. They do not change the original string. If you want to report an error, or if you want to make a suggestion, do not hesitate to send us an e-mail:. Example print "Hello" print 'Hello'. Exercise: Use the len method to print the length of the string. HOW TO. Your message has been sent to W3Schools.
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